1.

At 25^(@)C, the solubility product of Hg_(2)Cl_(2) is water is 3.2xx10^(-17) "mol"^(3) dm^(-9). What is the solubility of Hg_(2)Cl_(2) in water of 25^(@)C ?

Answer»

`1.2XX10^(-12) M`
`3.0xx10^(-6)M`
`2xx10^(-6)M`
`1.2xx10^(-16) M`

Solution :`{:(Hg_(2)Cl_(2),HARR,"Hg"_(2)^(2+),+,2Cl^(-)),(" "S,,S,,2S " "K_(sp)=S(2S)^(2)=4S^(3)):}`
`S=(K_(sp)//4)^(1//3)=(3.2xx10^(-17)//4)^(1//3)`
`=(8xx10^(-18))^(1//3)=2xx10^(-6)M`.


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