InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
At `27^(@)C`, a `5%` solution `("wt."//"vol")` of cane-sugar is isotonic with `8.77 g//litre` of urea solution. Find `m.wt`. of urea, if `m.wt`. of sugar is `342`. Also report the osmotic pressure of solution is `100 mL` each are mixed at `27^(@)C`. |
|
Answer» For isotonic solutions, having neither dissociation nor association nature of solutes. `C_(1) = C_(2)` or `(w_(1))/(m_(1)V_(1)) = (w_(2))/(m_(2)V_(2))` For sugar, For urea `(5)/((342 xx 100)/(1000)) = (8.77)/((m xx 1000)/(1000))` `:. m = (8.77 xx 342)/(5 xx 10) = 59.99` On mixing `100 mL` of cane sugar with `100 mL` urea solution, the total volume ow contains `200 mL` in which `5 g` cane sugar and `0.877 g` urea is present. Thus, `pi xx (200)/(1000) = [(5)/(342)+(0.877)/(60)] xx 0.0821 xx 300` `pi = 3.60 atm` |
|