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At `27^(@)C` temperature, the kinetic energy of an ideal gas is `E_(1^.)` If the temperature is increassed to `327^(@)C,` then the kinetic energy will beA. `(E_(1))/sqrt2`B. `sqrt2 E`C. `2E_(1)`D. `(E_(1))/2` |
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Answer» Correct Answer - C `E=3/2kTrArr E prop T` `therefore" "(E_(2))/(E_(1))=(T_(2))/(T_(1))=(600)/(300)=2rArr E_(2)=2E_(1)` |
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