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The rms speed of oxygen molecules in a gas is `v`. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will becomeA. vB. `sqrt2v`C. 2vD. 4v |
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Answer» Correct Answer - C As the rms speed is given by `v_(rms)=sqrt((3RT)/(M))rArrv_(rms)propsqrt((T)/(M))` When temperature is double and molecules dissociates into atoms, then `(v_(rms1))/(v_(rms2))=(sqrt((T)/(M)))/(sqrt((2T)/(M//2)))=(sqrt((T)/(M)))/(sqrt((4T)/(M)))=(sqrtT)/(sqrt4T)=1/2` If `v_(rms1) is v, then v_(rms2)` will be 2v. |
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