At 298 K temp. the K_(sp) of CaF_2 is 1.7 xx 10^(-10). One person daily drinks 2.5 L saturated water by CaF_2. Then how much gram CaF_2 present in his body ? (Molecular mass of CaF_2 is "78 g mol"^(-1))

At 298 K temp. the K_(sp) of CaF_2 is 1.7 xx 10^(-10). One person dail

1.	At 298 K temp. the K_(sp) of CaF_2 is 1.7 xx 10^(-10). One person daily drinks 2.5 L saturated water by CaF_2. Then how much gram CaF_2 present in his body ? (Molecular mass of CaF_2 is "78 g mol"^(-1))
Answer» SOLUTION :`S=3.489xx10^(-4)` M and 0.0683 G