At 298 K, the conductivity of a saturated solution of AgCl in water is – InterviewSolution

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1.	At 298 K, the conductivity of a saturated solution of AgCl in water is 2.6×10−6 S cm−1. Its solubility product at 298 K is:[Given :λ0(Ag+)=63.0 S cm2 mol−1λ0(Cl−)=67.0 S cm2 mol−1]
Answer» At $298 K$ , the conductivity of a saturated solution of $A g C l$ in water is $2.6 \times 10^{- 6} S c m^{- 1}$ . Its solubility product at $298 K$ is: [Given : $λ^{0} (A g^{+}) = 63.0 S c m^{2} m o l^{- 1}$ $λ^{0} (C l^{-}) = 67.0 S c m^{2} m o l^{- 1}$ ]

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