InterviewSolution
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InterviewSolution
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At 298 K, the pH of a lemon juice is 2.32. Calculate its `[H_(3)O^(+)]" and "[OH^(-)].` |
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Answer» pH of the solution `=2.32 , - log [H_(2)O^(+)] =2.32 or log [H_(3)O^(+)] =-2.32` `[H_(3)O]^(+) "Antilog" (-2.32) = "Antilog" (overset(-)(3).68) = 4.79 xx 10^(-3)` `[OH^(-)] = (K_(w))/[[H_(3)O^(+)]]=((1.0xx10^(-14)M^(-2)))/((4.79xx10^(-3)M))=2.09 xx 10^(-12)M` |
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