At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29`xx10^(-2)ohm^(-1)cm^(-1)` at 298K, what is cell contantA. `5.03xx10^(-1)cm^(-1)`B. `10.06xx10^(-1)cm^(-1)`C. `15.09xx10^(-1)cm^(-1)`D. `2.51xx10^(-1)cm^(-1)`

At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm.

1.	At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29`xx10^(-2)ohm^(-1)cm^(-1)` at 298K, what is cell contantA. `5.03xx10^(-1)cm^(-1)`B. `10.06xx10^(-1)cm^(-1)`C. `15.09xx10^(-1)cm^(-1)`D. `2.51xx10^(-1)cm^(-1)`
Answer» Correct Answer - A The cell cosntnat =l/a=R.k =39 ohm 1.29`xx10^(-2) ohm^(-1)cm^(-1)` `=5.03xx10^(-1)cm^(-1)`

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At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29`xx10^(-2)ohm^(-1)cm^(-1)` at 298K, what is cell contantA. `5.03xx10^(-1)cm^(-1)`B. `10.06xx10^(-1)cm^(-1)`C. `15.09xx10^(-1)cm^(-1)`D. `2.51xx10^(-1)cm^(-1)`

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