At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 `cm^(-1)` the electrical conductivity of the solution isA. `1.437xx10^(-2)ohm ^(-1)cm^(-1)`B. `1.473ohm^(-1)cm^(-1)`C. `1.06ohm^(-1)cm^(-1)`D. `3.5ohm^(-1)cm^(-1)`.

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell c

1.	At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 `cm^(-1)` the electrical conductivity of the solution isA. `1.437xx10^(-2)ohm ^(-1)cm^(-1)`B. `1.473ohm^(-1)cm^(-1)`C. `1.06ohm^(-1)cm^(-1)`D. `3.5ohm^(-1)cm^(-1)`.
Answer» Correct Answer - A The electrical conductivity, `k=(1)/(R)xx(l)/(a)` `=(1)/(35)xx0.503=1.437xx10^(-2)ohm^(-1)cm^(-1)`

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At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 `cm^(-1)` the electrical conductivity of the solution isA. `1.437xx10^(-2)ohm ^(-1)cm^(-1)`B. `1.473ohm^(-1)cm^(-1)`C. `1.06ohm^(-1)cm^(-1)`D. `3.5ohm^(-1)cm^(-1)`.

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