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At 298K the standard free energy of formation of `H_(2)O(l)` is `-256.5 kJ..mol`, while that of its ionisation to `H^(+)` & `OH^(-)` is `80 kJ//mol`. What will be emf at 298 K of the cell. `H_(2)(g,1 bar) |H^(+)(1M) || O_(2)(g,1bar)` Fill your answer by multiplying it with 10. |
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Answer» Correct Answer - `005` `H_(2) +H_(2)O +(1)/(2)O_(2) rarr 2H^(+) +2OH^(-)` `DeltaG^(@) =- 256.5 +2 xx 80 = -96.5 kJ` `-DeltaG^(@) = nFE^(@)` `+96.5 xx 1000 = 2 xx 96500 xx E^(@)` `E^(@) = 0.5` volt |
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