1.

At 400 K 1.5 g of an unknown substance is dissolved in solvent and the solution is made to 1.5 L. Its osmotic pressure is found to be 0.3 bar. Calculate the molar mass of the unknown substance.

Answer»

Solution :`DeltaT_(b) = K_(b) m = K_(b) XX W_(2) xx 1000//M_(2) xx W_(1)`
`M _(2) = K_(b)xx W_(2) xx 1000//Delta T _(b) xx W_(1)`
`= 7.5 xx 0.75 xx 1000//0.15 xx 200 = 187.5 g mol ^(-1)`


Discussion

No Comment Found