At 448^(@)the equilibrium constant(K_(c))for the reaction , H_(2) (g) + I_(2) (g) hArr 2 HI(g) , "is "50*5. Predict the direction in which the reaction will proceed to reach equilibrium at 448^(@)C, " if we start with " 2*0xx 10^(-2) " mol of " HI,1*0 xx 10^(-2) " mol of "H_(2) and 3*0 xx 10^(-2) "mol of " I_(2) " in a " 2*0 " L container"

At 448^(@)the equilibrium constant(K_(c))for the reaction , H_(2) (g)

1.	At 448^(@)the equilibrium constant(K_(c))for the reaction , H_(2) (g) + I_(2) (g) hArr 2 HI(g) , "is "505. Predict the direction in which the reaction will proceed to reach equilibrium at 448^(@)C, " if we start with " 20xx 10^(-2) " mol of " HI,10 xx 10^(-2) " mol of "H_(2) and 30 xx 10^(-2) "mol of " I_(2) " in a " 2*0 " L container"
Answer» SOLUTION :Q comes out to be `1*3` which is LESS than K .