1.

At `448^(@)` the equilibrium constant `(K_(c))` for the reaction , `H_(2) (g) + I_(2) (g) hArr 2 HI(g) , "is " 50*5.` Predict the direction in which the reaction will proceed to reach equilibrium at `448^(@)C, " if we start with " 2*0xx 10^(-2) " mol of " HI,1*0 xx 10^(-2) " mol of " H_(2) and 3*0 xx 10^(-2) "mol of " I_(2) " in a " 2*0 " L container"`

Answer» Correct Answer - Forward direction
Q comes out to be `1*3` which is less than K .


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