At 500 K , equilibrium constant K_(C) for the following reaction is 5 , (1)/(2) H_(2) (g) + (1)/(2) t_(2) (g) hArr HI (g) what would be the equilibrium constant K_(C) for the reaction 2 HI (g) hArr H_(2) (g) + I_(2) (g)

At 500 K , equilibrium constant K_(C) for the following reaction is 5

1.	At 500 K , equilibrium constant K_(C) for the following reaction is 5 , (1)/(2) H_(2) (g) + (1)/(2) t_(2) (g) hArr HI (g) what would be the equilibrium constant K_(C) for the reaction 2 HI (g) hArr H_(2) (g) + I_(2) (g)
Answer» `0.44` `0.04` `25` `2.5` Solution :`2 HI (g) hArr H_(2) (g) + I_(2) (g)` `K_(C) = ([H_(2)][I_(2)])/([HI]^(2)) = ?` `(1)/(2) H_(g) (g) + (1)/(2) I_(2) (g) hArr HI (g)` `K_(C)^(1) = ([HI])/([H_(2)]^((1)/(2)) [I_(2)]^((1)/(2))) = 5 IMPLIES ((1)/(K_(C)))^(2) = ([H_(2)] [I_(2)])/([HI]^(2)) = ((1)/(5))^(2) = K_(C)` `K_(C) = (1)/(25)= 0.04`