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At 500 K, equlibrium constant, `K_(c)` for the following reaction is 5. `1//2 H_(2)(g)+ 1//2(g)hArr HI (g)` What would be the equilibrium constant `K_(c)` for the reaction `2hi(g)hArrH_(2)(g)+l_(2)(g)`A. 0.04B. 0.4C. 25D. 2.5 |
Answer» Correct Answer - A For the reaction, `1//2H_(2)(g)+1//2 I_(2)(g)hArrHI(g),K_(c)=5` For the reaction, `HI(g)hArr1//2H_(2)(g)+1//2l_(2)(g),K_(c)=(1)/(5)` For the reaction `2HI(g)hArrH_(2)(g)+l_(2)(g),K_(c)=((1)/(5))^(1//2)` |
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