At 600^@ NH_4COONH_(2(s)) hArr 2NH_(3(g)) + CO_(2(g))is K_p=3.2xx10^2 "bar"^3 of equilibrium constant , So, calculate K_c. (R=0.0831 L bar K^(-1) "mol"^(-1))

At 600^@ NH_4COONH_(2(s)) hArr 2NH_(3(g)) + CO_(2(g))is K_p=3.2xx10^2

1.	At 600^@ NH_4COONH_(2(s)) hArr 2NH_(3(g)) + CO_(2(g))is K_p=3.2xx10^2 "bar"^3 of equilibrium constant , So, calculate K_c. (R=0.0831 L bar K^(-1) "mol"^(-1))
Answer» SOLUTION :`2.5812xx10^(-3) ("MOL"^(-1) L)^3`