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At `90^(@)C` , pure water has `[H_(3)O^(+)]` as `10^(-6)` mol `L^(-1)`. What is the value of `K_(w)` at `90^(@)C` ?A. `10^(-6)`B. `10^(-12)`C. `10^(-14)`D. `10^(-8)` |
Answer» Correct Answer - B `[H_(3)O^(o+)] = 10^(-6) = [overset(Theta)OH]` Because in pure water, `[H_(3)O^(o+)] = [overset(Theta)OH]` `K_(w) = [H_(3)O^(o+)] = [overset(Theta)OH]` `= 10^(-6) xx 10^(-6)` `= 10^(-12)` |
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