At a certain distance from a point charge, the field intensity is `500 V//m` and the potentil is `-3000 V`. The distance to the charge and the magnitude of the charge respectively areA. `6m` and `6muC`B. `4m` and `2muC`C. `6m` and `4muC`D. `6m` and `2muC`

At a certain distance from a point charge, the field intensity is `500

1.	At a certain distance from a point charge, the field intensity is `500 V//m` and the potentil is `-3000 V`. The distance to the charge and the magnitude of the charge respectively areA. `6m` and `6muC`B. `4m` and `2muC`C. `6m` and `4muC`D. `6m` and `2muC`
Answer» Correct Answer - D `500=(k\|q\|)/r^2`…………i `-3000=(k(-q))/r`……..ii Solving these two equations we get `r=6m` `:. \|q\|=(500r^2)/(k) `=((500)(6)^(2))/((9xx10^9)` `=2xx10^-6C` `=2muC`

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At a certain distance from a point charge, the field intensity is `500 V//m` and the potentil is `-3000 V`. The distance to the charge and the magnitude of the charge respectively areA. `6m` and `6muC`B. `4m` and `2muC`C. `6m` and `4muC`D. `6m` and `2muC`

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