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At a certain place the horizontal component of earth’s magnetic field is √3 times vertical component. The angle of dip at that place is-(a) 75° (b) 60° (c) 45° (d) 30° |
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Answer» Correct answer is (d) 30° tan δ = \(\frac{B_V}{B_H}\) = \(\frac{1}{\sqrt{3}}\) ⇒ δ = tan-1 \((\frac{1}{\sqrt{3}})\)= 30° |
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