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At a certain temperature and total pressure of 10^5 Pa ,iodine vapour contains 40% by volume of iodine atoms. Calaulate K_p for the equilibrium, 1_2(g)iff2I(g). |
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Answer» Solution :Percentage by VOLUME of gaseous iodine atoms=`40%` `therefore` Mole fraction of gaseous iodine ATOME =`40/100` `therefore` Partial pressure of gaseous iodine atome= `40/100xx10^5Pa=0.4xx10^5Pa` Partial pressure of gaseous `I_2=0.6xx10^5 PA` `therefore K_p=P_I^2/P_(I_2)=(0.4xx10^5)^2/(0.6xx10^5)=2.67xx10^4Pa` |
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