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At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms.I2(g) ⇌ 2I(g)Calculate KP for the equilibrium. |
Answer» Total pressure of equilibrium mixture = 105 Pa Partial pressure of iodine atoms (I) = \(\frac{40}{100}\) x (105 Pa) = 0.4 x 105 Pa Partial pressure of iodine molecules (I2) \(\frac{60}{100}\) x (105 Pa) = 0.6 x 105 Pa I2(g) (0.6 x 105 Pa) ⇌ 2I(g) (0.4 x 105 Pa) KP = \(\frac{p^2I}{pI_2}\) = \(\frac{(0.4 \times 10^5\, Pa)^2}{(0.6 \times 10^5\, Pa)}\) = 2.67 x 104 Pa |
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