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At a depth of 5 m below the free surface of a liquid, an air bubble of radius 2 mm is formed. The pressure inside the bubble will be (The surface tension of water is 20 xx 10^(-8)" N/m.") |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`2 xx 10^(5) N//m^(2)`<br/>`1.5 xx 10^(5) N//m^(2)`<br/>`3 xx 10^(5) N//m^(2)`<br/>`5 xx 10^(5) N//m^(2)`</p>Solution :Pressure inside the <a href="https://interviewquestions.tuteehub.com/tag/bubble-904920" style="font-weight:bold;" target="_blank" title="Click to know more about BUBBLE">BUBBLE</a> `=(P_(o)+<a href="https://interviewquestions.tuteehub.com/tag/pgh-591148" style="font-weight:bold;" target="_blank" title="Click to know more about PGH">PGH</a>)+(2T)/(r)` <br/> `=(10^(5)+10^(3)+10 xx 5)+2 xx (20 xx 10^(-8))/(2 xx 10^(-3))` <br/> `=150000 +20 xx 10^(-5)` <br/> `=1.5 xx 10^(5)N//m^(2))`</body></html> | |