At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.A. potential at its surface is `150 V`B. the charge on the shre is `50/3xx10^-10C`C. the electric field on the surface is `1500 V//m`D. the electric potential at its centre is `25 V`

At a distance of `5 cm and 10 cm` outward from the surface of a unifor

1.	At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.A. potential at its surface is `150 V`B. the charge on the shre is `50/3xx10^-10C`C. the electric field on the surface is `1500 V//m`D. the electric potential at its centre is `25 V`
Answer» Correct Answer - A::B::C `100=1/(4piepsilon_0).q/((R+0.05))` …….i `75=1/(4piepsilon_0).q/((R+0.05))`……..ii Solving these equations, we get `q=5/3xx10^-9C` and `R=0.1m` a. `V=1/(4piepsilon_0).q/R` `((9xx10^9)(5/3xx10^-9))/0.1` `=150V` c. `E=1/(4piepsilon_0).q/R^2=V/R=150/0.1` `=1500V//m` `d. V_(centre)=1.5v_(surface)`

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