InterviewSolution
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InterviewSolution
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At a given place on the Earth’s surface, the horizontal component of Earth’s magnetic field is 9 × 10^-5 T and the resultant magnetic field is 180 × 10^-6. Calculate the angle of dip at this place.(a) 45^o(b) 0^o(c) 60^o(d) 30^oThe question was asked by my college director while I was bunking the class.My question is from Earth’s Magnetism topic in section Magnetism and Matter of Physics – Class 12 |
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Answer» CORRECT choice is (c) 60^o The best EXPLANATION: GIVEN: H = 9 × 10^-5; R = 180 × 10^-6 = 18 × 10^-5 The required equation ➔ H=Rcosδ cosδ = \(\frac {H}{R}=\frac {9 \times 10^{-5}}{18 \times 10^{-5}}=\frac {1}{2}\) Therefore, δ = cos^-1\(\frac {1}{2}\)=60^o Thus, the angle of dip is 60^o. |
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