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At a given temperature and pressure, the equilibrium constant values for the equilibria 3A_2 + B_2 + 2C overset(K_1)hArr 2A_3 BC and A_3 BC overset(K_2)hArr 3/2[A_2] + 1/2B_2 +C The relation between K_1 and K_2 is |
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Answer» `k_1 = 1/sqrtK_2` `K_2= ([A]^(3/2)[B_2]^(1/2)[C])/([A_3BC])` `rArr K_2^2 =([A_2]^3[B_2][C]^2)/([A_3BC]^2)`...(2) COMPARING (1) & (2), `K_2^2 = 1/K_1 rArrK_2= K_1^((-1)/2)` |
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