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At a height of 0.4 m from the ground, the velocity of a projectile is →v=(6^i+2^j) m/s . The angle of projection is (g=10 m/s2 ). |
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Answer» At a height of 0.4 m from the ground, the velocity of a projectile is →v=(6^i+2^j) m/s . The angle of projection is (g=10 m/s2 ). |
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