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At a height of 0.4 m from the ground, the velocity of a projectile in vector form is→v=(6^i+2^j) m/s. The angle of projection is(g=10 m/s2) |
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Answer» At a height of 0.4 m from the ground, the velocity of a projectile in vector form is→v=(6^i+2^j) m/s. The angle of projection is |
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