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At a point on the right bisector of a magnetic dipole the magnetic potentialA. potential varies as `(1)/(r^(2))`B. Potential is zero at all points on the right bisectorC. field varies as `r^(2)`D. Field is perpendicular to the axis of dipole |
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Answer» Correct Answer - A `V=(mu_(0))/(4pi)(MaStheta)/(r^(2))` At right side of bisector,`theta=0` `therefore V oo(1)/(r^(2))` |
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