aT(AABC) 9rRAB 18 cm and BC15 cm, then find thelength of PQ.

1.	aT(AABC) 9rRAB 18 cm and BC15 cm, then find thelength of PQ.
Answer» Area of ∆ ABC/Area of ∆QRP = 9/4 AB = 18 cm , BC = 15 cm So PQ = ? We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides. Area of ∆ ABC/Area of ∆ QRP = AB2/QR2 = BC2/PR2 = AC2/QP2 Now substitute all given values and get 9/4 = 152/PQ2 Taking square root on both hand side , we get 3/2 = 15/PQ PQ = 10 cm

Answer»

Area of ∆ ABC/Area of ∆QRP = 9/4

AB = 18 cm , BC = 15 cm So PQ = ?

We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.

Area of ∆ ABC/Area of ∆ QRP = AB2/QR2 = BC2/PR2 = AC2/QP2

Now substitute all given values and get

9/4 = 152/PQ2

Taking square root on both hand side , we get

3/2 = 15/PQ

PQ = 10 cm

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