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At at what distance from the centre of the earth, the value of acceleration due to gravity g will be half that on the surface (R =radius of earth) |
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Answer» At height h, g' = g[R / (R + h)]2 (g/2) = g[R / (R + h)]2 (1 / √2) = [R / (R + h)] R + h = √2 R h = R(√2 – 1) h = 0.414 R hence distance from centre = R + h = R + 0.414 R = 1.414 R |
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