At constant temperature 80% AB dissociates into A_(2) and B_(2) then the equilibrium constant for 2AB_((g)) harr A_(2(g)) +B_(2(g))

At constant temperature 80% AB dissociates into A_(2) and B_(2) then t

1.	At constant temperature 80% AB dissociates into A_(2) and B_(2) then the equilibrium constant for 2AB_((g)) harr A_(2(g)) +B_(2(g))
Answer» 1 0.25 16 4 Solution : `K=(0.4 XX 0.4)/((0.2)^(2))=4`