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At definite temperature in open vessel decomposition of Ammonium carbonate take place and total pressure is P bar derive K_p. (NH_4)_2CO_(3(s)) hArr 2NH_(3(g)) + CO_(2(g)) +H_2O_((g)) |
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Answer» Solution :`{:("Reaction:",(NH_4)_2CO_(3(s)) hArr , 2NH_(3(g))+ , CO_(2(g)) + , H_2O_((g))),("Pressure at equilibrium:",,2x,X,x),("If total pressure P, So partial pressure",,(2P)/4,P/4,P/4):}` Total Pressure P=2x +x+ x = 4x `THEREFORE x=P/4` `therefore 2x=p_(NH_3)=(2P)/4` `x=p_(CO_2)=p_(H_2O)=P/4` `K_p=(p_(NH_3))^2(p_(CO)_2) (p_(H_2O))` `=((2P)/4)^2(P/4)(P/4)` `=P^4/64 "bar"^2` |
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