InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
At equilibrium, the concentrations of N, O, andNO in a sealed vessel at 800 K are:N = 3.0 x 10-3 M, 0, = 4.2 x 10-3 M andNO = 2.8 x 103MCalculate the equilibrium constant K, for thereaction :N. (g) + 0,(g) 2NO(g) |
|
Answer» Since you are given the concentrations at equilibrium for the three molecules you just need to plug those values into the equilibrium expression. First though, you need to write out the balanced chemical equation N2 + O2 --> 2NO The equilibrium expression for this equation would be Kc = [NO]2/[N2][O2] *don't forget the superscript on the [NO] due to the coefficient of the balanced equation (it's easy to mess that up!) After you have the equilibrium expression you can then plug the concentrations at equilibrium into the equation Kc = [.0030]2/[.0035][.0063] Solving this should get you the answer above answer is the correct answer |
|