At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl` added to `1 kg` water `(k_(b)=0.52 K mol^(-1)kg)` in order to raise the b.pt. of solution to `100 ^(@)C` is (assume `90%` ionisation of `NaCl`):A. `296.5 g`B. `281.25 g`C. `270 g`D. `310 g`

At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl

1.	At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl` added to `1 kg` water `(k_(b)=0.52 K mol^(-1)kg)` in order to raise the b.pt. of solution to `100 ^(@)C` is (assume `90%` ionisation of `NaCl`):A. `296.5 g`B. `281.25 g`C. `270 g`D. `310 g`
Answer» Correct Answer - A `Delta T = (1000 xx K_(b) xx w)/(m xx W)(1+alpha)` `5 = (1000 xx 0.52 xx w)/(58.5 xx 1000) xx (1.90)` , `(because alpha = 0.9)`

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At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl` added to `1 kg` water `(k_(b)=0.52 K mol^(-1)kg)` in order to raise the b.pt. of solution to `100 ^(@)C` is (assume `90%` ionisation of `NaCl`):A. `296.5 g`B. `281.25 g`C. `270 g`D. `310 g`

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