At idential tempreture and pressure , yhe rate of diffusion of hydrogen gas is 3sqrt3 times that of a hydrocarbon having moleculer formula C_(n)H_(2n-2) What is the value of n?

At idential tempreture and pressure , yhe rate of diffusion of hydroge

1.	At idential tempreture and pressure , yhe rate of diffusion of hydrogen gas is 3sqrt3 times that of a hydrocarbon having moleculer formula C_(n)H_(2n-2) What is the value of n?
Answer» 8 4 3 1 Solution :`gamma_(H_(2))/(gammac_(n_(H_(2n+2))))=sqrt(mc_(n)H_(2n+2)/m_(H_(2)))Rightarrow3sqrt3=sqrt(m_(c_(n_(H_(2n+n))))/2)` SQUARING on both sides and rearring `27xx2=m_(c_(n_(H_(2n-n))))` `54=n(12)+(2n-2)(1)` `54=12n+2n-2=14n-2` `n=(54+2)/14=56/14=4` .