At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3sqrt(3) times that of a hydrocarbon having molecular formula C_(n)H_(2n-2). What is the value of n ?

At identical temperature and pressure, the rate of diffusion of hydrog

1.	At identical temperature and pressure, the rate of diffusion of hydrogen gas is 3sqrt(3) times that of a hydrocarbon having molecular formula C_(n)H_(2n-2). What is the value of n ?
Answer» Solution :`(gammaH_(2))/(gammaC_(n)H_(2n-2))=SQRT((m_(C_(n)H_(2n-2)))/(m_(H_(2))))` `3sqrt(3)=sqrt((m_(C_(n)H_(2n-2)))/(2))` Squaring on both SIDES and REARRANGING `27xx2-m_(C_(n)H_(2n-2))` `54=n_(12)+(2n-2)(1)` `54=12n+2n-2` `n=(54+2)//14` `=56/14=4` `:.n=4`