At NTP, 1L of O_2 reacts with 3L of carbon monoxide. What will be the volume of CO and CO_2 after the reaction?

At NTP, 1L of O_2 reacts with 3L of carbon monoxide. What will be the

1.	At NTP, 1L of O_2 reacts with 3L of carbon monoxide. What will be the volume of CO and CO_2 after the reaction?
Answer» 1L `CO_2`, 1L CO 2L `CO_2`, 2L CO 1L `CO_2`, 2L CO 2L `CO_2`, 1L CO Solution :`UNDERSET(2 Vol )(2CO)+underset(1vol)(O_2) to underset(2vol)(2CO_2)` 1 vol of `CO_2` reacts with 2 vol of CO 1 L of `CO_2` reacts with 2 L of CO CO left after reaction = 3-2=1L 1L of `O_2` PRODUCES 2L of `CO_2` Hence, after the reaction, CO =1L, `CO_2=2L`