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At NTP, the ratio of molecules in 1cc of oxygen to that in 1cc of hydrogen is : (a) 1 : 1 (b) 1 : 4 (c) 1 : 16 (d) 1 : 2 |
Answer» <p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (a) 1 : 1</strong></span></span></p><p class="MsoNormal" style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">From the formula, the number of molecules in V litres of gas at NTP is = NV/22.4</span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">It represents that at NTP, all the gases have same number of molecules in same volume. Hence, ratio of molecules in both cases is 1 : 1.</span></span></p> | |