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At one time H_(2)O_(2) was obtained by electrolysis of 50% H_(2)SO_(4) The process of electrolysis involves following reaction : 2H_(2)SO_(4) rarr 2H^(+)+2HSO_(4)^(-) At cathode: 2H^(+)+2e^(-) rarr H_(2)uarr At anode: 2HSO_(4)^(-)rarr X+2e^(-) X+H_(2)O rarr Y+Z, Y+H_(2)Orarr Z+H_(2)O_(2) The number of -OH groups in X: |
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Answer» 3 |
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