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At ordinary temperature, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures they may also have vibrational energy. As a result of this at higher temperatures (Cv = molar heat capacity at constant volume) :–(a) Cv = 3R/2 for a monoatomic gas(b) Cv > 3R/2 for a monoatomic gas(c) Cv > 5R/2 for a diatomic gas(d) Cv = 5R/2 for a diatomic gas |
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Answer» Correct option (c) Cv > 5R/2 for a diatomic gas Explanation: Monoatomic gas Cv = 3R/2 This value is same for high temperature also, In case of diatomic gas Cv = 5R/2 (at low temperature) Also,Cv > 5R/2 (at high temperature due to vibrational kinetic energy) |
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