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At resonance, `V_(L)` and `V_(C )` both very much greater than the applied potential, `V` itself. The quantity factor for an `LCR` circuit in resonance is given by `Q = (X_(L))/(R )`. In pratice, `Q = 200` has been achieved. At resonance, the capacitor has been adjusted for (1). `200 xx 10^(-6) mu F` (2) `0.00013 mu F` (3). `0.0012 mu F` (4). `0.0013 F` At resonance, the potential difference across the inductance is (1) `1.3 V` (2) `13 V` (3). `0.3 V` (d) none of these The potential across the capacitor at resosnance is (1) `1.3 V` (2) `13 V` (3) `lt 13 V` (4) none of these The `Q` factor is (1) `(V_(L))/(V_(C ))` (2) `(V_(C ))/(V_(L))` (3) `(V_(C ))/(V)` (d) `(V_(L))/(V)` (e) choose the right statement. (1) `V_(L)+V_(C)` can be greater than `V_("applied")` (2) `V_(L)+V_(C)=V_("applied")` (3) `V_(L)+V_(C) lt V_("applied")` (4) none of these

Answer» Correct Answer - 2, 3, 1, (3,4)


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