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At room temperature copper has free electron density of `8.4xx10^(28) per m^(3)` . The copper conductor has a cross-section of `10^(-6)m^(2)` and carries a current of 5.4 A. What is the electron drift velocity in copper? |
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Answer» Here, `n=8.4 xx 10^(28) m^(-3)` , `A=10^(-6) m^(2), I=5.4 A` `v_(d)=(I)/(n Ae) =5.4/((8.4xx10^(28))xx(10^(-6))xx(1.6xx10^(-19)))` `=0.4 xx 10^(-3) m//s =0.4mm//s` |
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