At some temperature and under a pressure of 4 atm, PCI_(5) is 10% dissociated. Calculate the pressure at which PCI_(5) will be 20% dissociated, temperature remaining same

At some temperature and under a pressure of 4 atm, PCI_(5) is 10% diss

1.	At some temperature and under a pressure of 4 atm, PCI_(5) is 10% dissociated. Calculate the pressure at which PCI_(5) will be 20% dissociated, temperature remaining same
Answer» <P>9.7 atm 0.97 atm 97 atm 7.9 atm Solution :`UNDERSET(1-alpha)underset(1)(PCl_(5(g))) harr underset(alpha)underset(0)(PCl_(3(g)))+underset(alpha)underset(0)(Cl_(2(g)))` `KP=(alpha^(2))/((1-alpha))[(p)/(1+alpha)]^(1)` Since, Kp remains constant and therefore EQUATING for `alpha=0.1` at p=4atm and `alpha=0.2` at p=p atm `((0.1)^(2))/(0.9) xx (4)/(1.1)=((0.2)^(2) xx p)/(0.8 xx 1.2) implies p=0.97` atm