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At STP 1.12 litre of `H_(2)` is obtained on flowing a current for 965 seconds in a solution . The value of current isA. 10B. 1C. 1.5D. 2 |
Answer» Correct Answer - A `2H^(+)+underset(2"mole"2xx96500C)(2e^(-))rarrunderset("1mole"22.4"lt")(H_(2)` To liberate 22.5 lt of `H_(2)` gas, electricity required `=2xx96500C` To liberate 1.12 lt of `H_(2)` gas, electricity required `=(2xx96500xx1.12)/(965"sec")=1 0` ampere |
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