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At `STP`, the order of mean square velocity of molecules of `H_(2)`, `N_(2)`, `O_(2)`, and `HBr` isA. `H_(2)ltN_(2)ltO_(2)ltHBr`B. `HBrltO_(2)ltN_(2)ltH_(2)`C. `H_(2)ltN_(2)=O_(2)ltHBr`D. `HBrltO_(2)ltH_(2)ltN_(2)` |
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Answer» Correct Answer - B The root mean square velocity of gas molecule at STP given by `U_(rms)=sqrt((3RT)/(M))` `therefore` As the molar mass of gas increases, then `U_(rms)` will decrease, so the order of `U_(rms)` of these gases is `HBr ltO_(2) lt N_(2) lt H_(2)` |
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