1.

At t = 2 sec., a particles is at (1,0,0,). It moves towards (4,4,12) with a constant speed of 65 m/s. The position of the paritcle is measured in metres and the time is sec. Assuming constant velocity, the position of the particle at t = 3 s is,

Answer»

`(13hati-120hatj+40hatk)`
`(40hati+31hatj-120hatk)`
`(13hati-40hatj+12hatk)`
`(45hati+60hatj+180hatk)`

Solution :`vecS=vecVt`
`vecr_(F)-HATI=(65(3hati+4hatj+12hatk))/(13)xx3`
`vecr_(f)=46veci+60vecj+180veck`


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