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At t = 2 sec., a particles is at `(1,0,0,).` It moves towards `(4,4,12)` with a constant speed of 65 m/s. The position of the paritcle is measured in metres and the time is sec. Assuming constant velocity, the position of the particle at t = 3 s is,A. `(13hati-120hatj+40hatk)`B. `(40hati+31hatj-120hatk)`C. `(13hati-40hatj+12hatk)`D. `(45hati+60hatj+180hatk)` |
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Answer» Correct Answer - D `vecS=vecVt` `vecr_(f)-hati=(65(3hati+4hatj+12hatk))/(13)xx3` `vecr_(f)=46veci+60vecj+180veck` |
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