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At the expense of two ATP molecules, how many phosphate groups are present on the fructose in the third step of glycolysis?(a) 2(b) 3(c) 4(d) 5 |
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Answer» Correct choice is (a) 2 To explain I would say: Glucose is first phosphorylated at the expense of one ATP molecule, rearranging to form fructose phosphate and then phosphorylation takes place again leading to a total of two phosphate groups attached to the fructose chain. |
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