1.

At the mount of the tap area of cross-section is 2.0cm^(2) and the speed of water is 3m//s. The area of cross-section of the water column 80 cm below the tap is (use g=10m//s^(2))

Answer»

SOLUTION :(i) `(d_(0))/(d_(W))=("voulume of liquid displaced")/("Volulme of the OBJECT")`
`=("RISE in LEVEL") xx (A_(c )-A_(0))/(A_(0)xx(1_(0)))`
(ii) `0.6 g cm^(-s)`


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