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At the mount of the tap area of cross-section is `2.0cm^(2)` and the speed of water is `3m//s`. The area of cross-section of the water column 80 cm below the tap is (use `g=10m//s^(2))`A. `0.6cm^(2)`B. `1.2cm^(2)`C. `1.5cm^(2)`D. `2.0cm^(2)` |
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Answer» Correct Answer - B `v_(2)^(2)=v_(1)^(2)+2gh,A_(1)v_(1)=A_(2)v_(2)` |
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